# If $a,b,c$ are all different and $\begin{vmatrix}a&a^3&a^4-1\\b&b^3&b^4-1\\c&c^3&c^4-1\end{vmatrix}=0$ then the value of $abc(ab+bc+ca)$ is
$\begin{array}{1 1}(A)\;a+b+c&(B)\;0\\(C)\;a^2+b^2+c^2&(D)\;a^2-b^2+c^2\end{array}$