If $ax^3+bx^2+cx+d=\begin{vmatrix}x^2&(x-1)^2&(x-2)\\(x-)^2&(x-2)^2&(x-3)^2\\(x-2)^2&(x-3)^2&(x-4)^2\end{vmatrix}$ then
$\begin{array}{1 1}(A)\;\text{a=1,b=2,c=3,d=-8}\\(B)\;\text{a=-1,b=2,c=3,d=-8}\\(C)\;\text{a=0,b=0,c=0,d=8}\\(D)\;\text{a=0,b=0,c=0,d=-8}\end{array}$