Prove the following by using the principle of mathematical induction for all $n \in N$ $1+ \large\frac{1}{(1+2)}$$+ \large\frac{1}{(1+2+3)}$$+...+ \large\frac{1}{(1+2+3...n)}$$= \large\frac{2n}{(n+1)}$

Share

Please log in or register to add a comment.