If $\;cosec\theta = \large\frac{p+q}{p-q}\;(p \neq q \neq 0)\;$, then $\;|cot(\large\frac{\pi}{4} + \large\frac{\theta}{2})|\;$ is equal to :

Question

$(a)\;\sqrt{\large\frac{p}{q}} \qquad(b)\;\sqrt{\large\frac{q}{p}}\qquad(c)\;\sqrt{pq}\qquad(d)\;pq$