For the reaction ,$\;2N_{2}O_{5} \to 4 NO_{2}+O_{2}\;$ , the rate equation can be expressed in two ways $\;- \large\frac{d[N_{2}O_{5}]}{dt} = k \normalsize N_{2}O_{5}\;$ and $\;+ \large\frac{d[NO_{2}]}{dt} = k^{'} \normalsize N_{2}O_{5}\;$ $\;k\;$ and $\;k^{'}\;$ are related as :

Question

$(a)\;k=k^{'} \qquad(b)\;2k=k^{'}\qquad(c)\;k=2k^{'}\qquad(d)\;k=4k^{'}$