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JEEMAIN-2014
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Q)
A body of mass 5 kg under the action of constant force
→
F
=
F
x
ˆ
i
+
F
y
ˆ
j
has velocity at t=0s as
→
v
=
(
6
ˆ
i
−
2
ˆ
j
)
m
/
s
and at t=10s as
→
v
=
+
6
ˆ
j
m
/
s
. The force
→
F
is :
(
a
)
(
−
3
ˆ
i
+
4
ˆ
j
)
N
(
b
)
(
−
3
5
ˆ
i
+
4
5
ˆ
j
)
N
(
c
)
(
3
ˆ
i
−
4
ˆ
j
)
N
(
d
)
(
3
5
ˆ
i
−
4
5
ˆ
j
)
N
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