$\Large\int \frac {x \sin^{-1}x}{\sqrt{1-x^2}} \normalsize dx=$ $$(a)\;\sqrt{1-x^2}\sin^{-1}x\qquad (b)\;x\sin^{-1}x\qquad(c)\;x-\sqrt{1-x^2}\sin^{-1}x\qquad(d)\;(\sin^{-1}x)^2$$

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