$\int x\tan^{-1}x dx=$ \[(a)\;\bigg(\frac{x^2+1}{2}\bigg) \tan^{-1}x- \frac{x}{2} \qquad (b)\;\bigg(\frac{x^2+1}{2}\bigg)+\tan^{-1}x-x \qquad(c)\;(x^2+1)\tan^{-1}x-x \qquad(d)\;(x^2+1) \tan^{-1}x+x \]

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