Email
Chat with tutors
logo

Ask Questions, Get Answers

X
 
Questions  >>  Archives  >>  JEEMAIN-2014
Answer
Comment
Share
Q)

If the volume of a spherical ball is increasing at the rate of $\;4 \pi \;cc/sec\;$ , then the rate of increase of its radius (in cm/sec) , when the volume is $\;288 \pi\;cc\;$ , is :

$(a)\;\large\frac{1}{6}\qquad(b)\;\large\frac{1}{9}\qquad(c)\;\large\frac{1}{36}\qquad(d)\;\large\frac{1}{24}$

Please log in or register to answer this question.

Home Ask Tuition Questions
Your payment for is successful.
Continue
...