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JEEMAIN-2014
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Q)
Let function F be defined as
F
(
x
)
=
x
∫
1
e
t
t
d
t
, x > 0 then the value of the integral
x
∫
1
e
t
t
+
a
d
t
, where a > 0 , is :
(
a
)
e
a
[
F
(
x
)
−
F
(
1
+
a
)
]
(
b
)
e
−
a
[
F
(
x
+
a
)
−
F
(
a
)
]
(
c
)
e
a
[
F
(
x
+
a
)
−
F
(
1
+
a
)
]
(
d
)
e
−
a
[
F
(
x
+
a
)
−
F
(
1
+
a
)
]
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