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Let function F be defined as F(x)=x1ettdt , x > 0 then the value of the integral x1ett+adt , where a > 0 , is :

(a)ea[F(x)F(1+a)](b)ea[F(x+a)F(a)](c)ea[F(x+a)F(1+a)](d)ea[F(x+a)F(1+a)]

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