$(a)\;\large\frac{x}{1}=\large\frac{y}{-1}=\large\frac{z}{-2}\qquad(b)\;\large\frac{x-1}{1}=\large\frac{y+1}{-1}=\large\frac{z}{-2}\qquad(c)\;\large\frac{x-1}{1}=\large\frac{y+1}{-1}=\large\frac{z}{1}\qquad(d)\;\large\frac{x}{-2}=\large\frac{y}{1}=\large\frac{z}{2}$