$\Large \frac {1}{x(x^4-1)^4}=$ $$(a)\;\log \bigg[\frac{x^4}{x^4-1}\bigg]\qquad (b)\;\frac{1}{2}\log \bigg[\frac{x^2+1}{x^2+1}\bigg]\qquad(c)\;\frac{1}{4} log \bigg[\frac{x^4-1}{x^4}\bigg]\qquad(d)\;\log \frac{x(x^2-1}{x^2+1}\bigg]$$

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