When the planet Jupiter is at a distance of 824.7 million kilometers from the Earth, its angular diameter is measured to be 35.72" of arc. Calculate the diameter of Jupiter.

Question

$\begin {array} {1 1} (A)\;14.35 \times 10^5kg & \quad (B)\;143.5 \times 10^5kg \\ (C)\;143 \times 10^5kg & \quad (D)\;1.435 \times 10^5kg \end {array}$