Find the value of p so that the lines $ \large\frac{1-x}{3}=\frac{7y-14}{2p}=\frac{z-3}{2}$ and $\large\frac{7-7x}{3p}=\frac{y-5}{1}=\frac{6-z}{5} $ are right angles.

Share

Please log in or register to add a comment.