Show that the function f defined as follows, is continuous at x = 2 but not differentiable $f(x) = \left\{ \begin{array}{l l}3x-2, & \quad { 0 < x \leq 1} \\ 2x^2-x, & \quad { 1 < x \leq 2} \\ 5x-4, & \quad { x > 2 } \end{array} \right. $

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