If $\hat{a}\;and\;\hat{b}$ are unit vectors inclined at an angle $\theta$,then prove that $$(a)\;\cos \frac{\theta}{2}=\frac{1}{2}|\hat{a}+\hat{b}|\qquad(b)\;\tan \frac{\theta}{2}=\frac {|\hat{a}-\hat{b}|}{|\hat{a}+\hat{b}|}$$

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