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Questions  >>  CBSE XI  >>  Math  >>  Binomial Theorem
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Find the middle term in the expansion of $(3x-\large\frac{x^3}{6})^9$

$\begin{array}{1 1}(A)\;\large\frac{189}{8}\normalsize x^{17};-\large\frac{21}{16}\normalsize x^{19}\\(B)\;\large\frac{189}{8}\normalsize x^{17};-\large\frac{22}{16}\normalsize x^{15}\\(C)\;\large\frac{8}{189}\normalsize x^{17};-\large\frac{21}{16}\normalsize x^{19}\\(D)\;\large\frac{8}{189}\normalsize x^{17};-\large\frac{25}{4}\normalsize x^{13}\end{array} $

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