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CBSE XI
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Math
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Binomial Theorem
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If the $6^{th}$ term in the expansion of $\big(\large\frac{1}{x^{8/3}}+$$x^2\log _{10} x\big)^{8}$ is 5600 then the value of $x$ is
$\begin{array}{1 1}(A)\;8\\(B)\;9\\(C)\;10\\(D)\;11\end{array} $
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