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Questions  >>  CBSE XI  >>  Math  >>  Binomial Theorem
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If the $6^{th}$ term in the expansion of $\big(\large\frac{1}{x^{8/3}}+$$x^2\log _{10} x\big)^{8}$ is 5600 then the value of $x$ is

$\begin{array}{1 1}(A)\;8\\(B)\;9\\(C)\;10\\(D)\;11\end{array} $

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