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Questions  >>  CBSE XI  >>  Math  >>  Straight Lines
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Choose the correct answer from the given four options. A point equidistant from the lines 4x+3y+10=0,5x12y+26=0 and 7x+24y50=0 is

(A)(1,1)(B)(1,1)(C)(0,0)(D)(0,1)

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