Find the area of the part of the circle $x^2+y^2=16$ which is exterior to the parabola $y^2=6x$.

Question

$\begin{array}{1 1}\large\frac{4}{3}[8\pi-\sqrt 3] sq.units \\ \large\frac{4}{3}[8\pi+\sqrt 3] sq.units \\\large\frac{4}{3}[8\pi-\sqrt 5] sq.units. \\ \large\frac{2}{3}[8\pi-\sqrt 3] sq.units \end{array}$