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Questions  >>  CBSE XI  >>  Math  >>  Probability
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A sample space consists of a elementary outcomes $e_1,e_2........e_9$ whose probabilities are $P(e_1)=P(e_2)=0.08,P(e_3)=P(e_4)=P(e_5)=.1,P(e_6)=P(e_7)=.2,P(e_8)=p(e_9)=0.07$.Suppose $A=\{e_1,e_5,e_8\},B=\{e_2,e_5,e_8,e_9\}$.Calculate $P(\bar{B})$ from P(B),also calculate $P(\bar{B})$ directly from the elementary outcomes of $\bar{B}$.

$\begin{array}{1 1}(A)\;0.68\\(B)\;0.78\\(C)\;0.48\\(D)\;0.18\end{array} $

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