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Questions  >>  CBSE XI  >>  Math  >>  Probability
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In a non-leap year,the probability of having 53 tuesdays or 53 wednesdays is

$\begin{array}{1 1}(A)\;\large\frac{1}{7}\\(B)\;\large\frac{2}{7}\\(C)\;\large\frac{3}{7}\\(D)\;\text{None of these}\end{array} $

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