Find the coordinates of the focus, axis of the parabola, the equation of the directrix and the length of the latus rectum for the following : $x^2=6y$

Question

$\begin {array} {1 1} (A)\;focus : \bigg(0, -\large\frac{3}{2} \bigg), Equation \: of \: directrix : 2y-3=0 , Axis : y - axis , Length \: of \: the \: L.R : 6 \\ (B)\;focus : \bigg( -\large\frac{3}{2}, 0 \bigg), Equation \: of \: directrix : 2x+3=0 , Axis : x - axis , Length \: of \: the \: L.R : 6 \\ (C)\; focus : \bigg(0, \large\frac{3}{2} \bigg), Equation \: of \: directrix : 2y+3=0 , Axis : y - axis , Length \: of \: the \: L.R : 6\\ (D)\;focus : \bigg( \large\frac{3}{2}, 0 \bigg), Equation \: of \: directrix : 2x-3=0 , Axis : x - axis , Length \: of \: the \: L.R : 6 \end {array}$