The standard reduction potentials,$E^{\large\circ}$,for the half reactions are $Zn^{2+}+2e^-=Zn,E^{\large\circ}=-0.76V$ and $Fe^{2+}+2e^-=Fe,E^{\large\circ}=-0.41V$.The emf of the cell involving the reaction $Fe^{2+}+zn\rightarrow Zn^{2+}+Fe$ is

Question

$\begin{array}{1 1}-0.35V\\1.17V\\0.35V\\-1.17V\end{array} $