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JEEMAIN and NEET
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Chemistry
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Electrochemistry
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Consider the cell potentials $E^{\large\circ}_{Mg^{2+}|Mg}=-2.37V$ and $E^{\large\circ}_{Fe^{3+}|Fe}=-0.04V$.The best reducing agent would be
$\begin{array}{1 1}Mg^{2+}\\Fe^{3+}\\Mg\\Fe\end{array} $
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