Adding powdered Pb and Fe to a solution containing 1.0M in each of $Pb^{2+}$ and $Fe^{2+}$ ions would result into the formation of

Question

$\begin{array}{1 1}\text{more of Pb and }Fe^{2+}\text{ ions}\\\text{more of Fe and }Pb^{2+}\text{ ions}\\\text{more of Fe and Pb}\\\text{more of }Fe^{2+}\text{ and }Pb^{2+}\text{ ions}\end{array} $