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Questions  >>  JEEMAIN and NEET  >>  Chemistry  >>  Solutions
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The vapour pressure of a pure liquid A is 80 mmHg at 300K.It forms an ideal solution with liquid B.When the mole fraction of B is 0.4,the total pressure was found to be 88 mmHg.The vapour pressure of liquid A would be

$\begin{array}{1 1}\text{84 mmHg}\\\text{90 mmHg}\\\text{100 mmHg}\\\text{120 mmHg}\end{array} $

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