Calculate the electronegativity of Flourine, given the following: $E_{H-H} = 104.2 \; kcal\;mol^{-1},\; E_{F-F} = 36.6\; kcal\;mol^{-1},\;E_{H-F} = 134.6 \; kcal\;mol^{-1},\;\chi_H = 2.1$

Question

$\begin{array}{1 1} 3.766 \\ 3.543 \\ 3.98 \\ 3.666 \end{array}$