Using X-rays of wavelength 154.1pm and starting from the glancing angle,the reflection from silver crystal was found to occur at $\theta=22.20^{\large\circ}$.Calculate the spacing between the planes of Ag atoms that gave rise to the above reflection.($\sin 22.20^{\large\circ}=0.3778$)

Question

$\begin{array}{1 1}204pm\\304pm\\604pm\\704pm\end{array}$