A metal (atomic mass =50) has a body-centred cubic lattice.The density of the metal is $5.91gcm^{-3}$.Find out the volume of the unit cell.$[N_A=6.023\times 10^{23}]$

Question

$\begin{array}{1 1}2.809\times 10^{-23}cm^3\\1.809\times 10^{-23}cm^3\\0.809\times 10^{-23}cm^3\\4.809\times 10^{-23}cm^3\end{array}$