Henry’s law constant for the molality of methane in benzene at 298 K is $4.27 \times 10^5$ mm Hg. Calculate the solubility of methane in benzene at 298 K under 760 mm Hg.

Question

$\begin{array}{1 1}1.78\times 10^{-3}\\2.78\times 10^{-3}\\3.78\times 10^{-3}\\4.78\times 10^{-3}\end{array}$