If the freezing point depression constant of a solvent is $20.0\;K\;kg\;mol^{-1}$. If its $\Delta_{fus} H^0_m=2.74\;kJ\;mol^{-1}$ and its molar mass is $84.2\;g\;mol^{-1}$ the normal freezing point of the solvent would be about

Question

$\begin{array}{1 1} 308.2\;K \\ 298.1\;K \\ 249.8\;K \\ 279.8\;K \end{array} $