A bus starts from rest with an acceleration of $1\;ms^{-2}$ A man who is $48\;m$ behind the bus starts with a uniform velocity of $10\;ms^{-1}$. The minimum time after which the man will catch the bus is

Question

$\begin{array}{1 1} 4.8\;s \\ 8\;s \\ 10\;s \\12\;s \end{array}$