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Questions  >>  JEEMAIN and NEET  >>  Physics  >>  Class11  >>  Laws of Motion
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A particle of mass m is suspended from a ceiling through a string of length L. The particle moves in a horizontal circle of radius r. Find the speed of the particle.

$\begin{array}{1 1} v=rg\;\tan\;\theta \\ v= \sqrt{(rg\;\tan \theta)} \\v=mg \;\cos \theta\\ v=\sqrt{(mg \cos \theta )}\end{array} $

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