A position dependent force $\overrightarrow{F}=(7-2x+3x^2)N$ acts on a small object of mass 2kg to displace it from $x=0$ to $x=5m$.The work done in joules is

Question

$\begin{array}{1 1}70\;J\\270\;J\\35\;J\\135\;J\end{array}$