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JEEMAIN and NEET
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Physics
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Class11
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Work, Power and Energy
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A force $F_x$ acts on a particle.The force is related to the position of the particle by the formula $F_x=Cx^3$,where $C$ is a constant.Find the work done by this force on the particle when the particle moves from $x=1.5\;m$ to $x=3\;m$.
$\begin{array}{1 1}19C\;J\\29C\;J\\39C\;J\\10C\;J\end{array} $
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