The value of k so that the system of linear equation has no solution $(3k+1)x+3y-2=0; (k^2+1)x +(k-2)y-5=0$ is

Question

$(A) \; k=1 \\(B)\;k=-1 \\(C)\; k=\pm 1 \\(D)\;none\;of\;these$