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Questions  >>  CBSE XI  >>  Math  >>  Conic Sections
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Find the equation of the following parabola : Vertex at $(0,4)$,focus at $(0,2)$.

$\begin{array}{1 1}x^2=8y-32\\y^2=8x-32\\x^2=32-8y\\y^2=32-8x\end{array} $

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