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Questions  >>  CBSE XI  >>  Math  >>  Conic Sections
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Find the equation of the hyperbola with vertices $(0,\pm 7),e=\large\frac{4}{3}$.

$\begin{array}{1 1}\large\frac{9x^2}{343}-\frac{y^2}{49}\normalsize =1\\\large\frac{9x^2}{343}+\frac{y^2}{49}\normalsize =1\\\large\frac{9x^2}{343}+\frac{y^2}{49}\normalsize =-1\\\large\frac{9x^2}{343}-\frac{y^2}{49}\normalsize =-1\end{array} $

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