$\begin{array}{1 1}\large\frac{4x^2}{5}+\frac{4y^2}{1}\normalsize =1\\\large\frac{4x^2}{1}+\frac{4y^2}{5}\normalsize =1\\\large\frac{5x^2}{4}+\frac{y^2}{4}\normalsize =1\\\large\frac{x^2}{4}+\frac{5y^2}{4}\normalsize =1\end{array} $
