The equation of the hyperbola with vertices at $(0,\pm 6)$ and eccentricity $\large\frac{5}{3}$ is _________ and its foci are ___________

Question

$\begin{array}{1 1}\large\frac{y^2}{36}-\frac{x^2}{64}\normalsize =1,(0,\pm 10)\\\large\frac{y^2}{36}+\frac{x^2}{64}\normalsize =-1,(0,\pm 12)\\\large\frac{x^2}{36}-\frac{y^2}{64}\normalsize =-1,(0,\pm 20)\\\large\frac{y^2}{64}-\frac{x^2}{36}\normalsize =1,(0,\pm 15)\end{array}$