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Questions  >>  CBSE XI  >>  Math  >>  Conic Sections
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Q)

If the vertex of the parabola is the point $(-3,0)$ and the directrix is the line $x+5=0$,then its equation is

$\begin{array}{1 1}y^2=8(x+3)\\x^2=8(y+3)\\y^2=-8(x+3)\\y^2=8(x+5)\end{array} $

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