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CBSE XI
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Math
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Conic Sections
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Q)
If the vertex of the parabola is the point $(-3,0)$ and the directrix is the line $x+5=0$,then its equation is
$\begin{array}{1 1}y^2=8(x+3)\\x^2=8(y+3)\\y^2=-8(x+3)\\y^2=8(x+5)\end{array} $
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