At a point on level ground, the angle of elevation of a vertical tower is found to be such that its tangent is $\large\frac{5}{12}$ . On walking $192\;m$ towards the tower. the tangent of the angle of elevation is $\large\frac{3}{4}$. The height of the tower is

Question

$\begin{array}{1 1}(A) \; 200 \\(B)\;180 \\(C)\;240 \\ (D)\;300 \end{array}$