Email
Chat with tutors
logo

Ask Questions, Get Answers

X
 
Answer
Comment
Share
Q)

Of all the closed cylindrical cans (right circular), of a given volume of 100 cubic centimetres, find the dimensions of the can which has the minimum surface area?

$\begin{array}{1 1} \frac{10}{\pi}\big(\frac{\pi}{50}\big)^{\frac{2}{3}}cm \\ \frac{100}{\pi}\big(\frac{\pi}{20}\big)^{\frac{2}{3}}cm \\ \frac{100}{\pi}\big(\frac{\pi}{50}\big)^{\frac{2}{3}}cm \\ \frac{100}{\pi}\big(\frac{-\pi}{50}\big)^{\frac{2}{3}}cm \end{array} $

1 Answer

Home Ask Tuition Questions
Your payment for is successful.
Continue
...