The incircle of a $\Delta ABC$, touches the sides BC , CA and AB at D, E and F respectively. Then $AF+BD+CE = AE+BF+CD=$ _______ perimeter of $\Delta ABC$

Question

$\begin{array}{1 1} 2 \\ \large\frac{1}{2} \\ 1 \\\text{none of the above} \end{array}$