If $\large\frac{2^{m+n}}{2^{n-m}}$$=16$ and $a =2^{\large\frac{1}{10}}$, then $\large\frac{a^{2m+n-p}}{(a^{m-2n+2p})^{-1}}$=

Question

$\begin{array}{1 1} 2 \\ \large\frac{1}{4} \\ 9 \\ \large\frac{1}{8} \end{array}$