The equations to a pair of opposite sides of parallelogram are $x^2-5x+6=0$ and $y^2-6y+5=0$ . The equations to its diagonals are

Question

$\begin{array}{1 1} x+4y=13\; and \; y=4x-7 \\ 4x+y=13\; and \; 4y=x-7 \\ 4x+y=13\; and \; y=4x-7 \\ y-4x=13\; and \; y+4x=7 \end{array}$