In triangle ABC $\angle B = \large\frac{\pi}{3}$ and $\angle C = \large\frac{\pi}{4}$ Let d divide BC instantly in the ratio $1:3$ . Then $\large\frac{\sin \angle BAD}{\sin \angle CAD}$ equals

Question

$\begin{array}{1 1} \large\frac{1}{\sqrt 6} \\ \large\frac{1}{3} \\ \large\frac{1}{\sqrt 3} \\\sqrt{\large\frac{2}{ 3}} \end{array}$