If vector $\overrightarrow{A} =2 \overrightarrow{i}+3 \overrightarrow{j}+4 \overrightarrow{k};\overrightarrow{B}=\overrightarrow{i}+\overrightarrow{j}+5 \overrightarrow{k}$ and $\overrightarrow{c}$ form a left handed system , then $\overrightarrow{C}$ is

Question

$\begin{array}{1 1} 11 \overrightarrow{i}- 6\overrightarrow{j} - \overrightarrow{k} \\ -11\overrightarrow{i} +6\overrightarrow{j}+\overrightarrow{k} \\11\overrightarrow{i} -6\overrightarrow{j}+\overrightarrow{k} \\ 11 \overrightarrow{i} +6\overrightarrow{j}-\overrightarrow{k} \end{array}$