If P is nearly equal to q and $n >14$ such that $ \large\frac{(n+1)p+(n-1)q}{(n-1)p +(n-1)q} =\frac{p}{q}^k$ then the value of k is

Question

$\begin{array}{1 1} n \\ \large\frac{1}{n} \\n+1 \\\large\frac{1}{n+1} \end{array} $